Questions
A long solenoid has 500 turns. When a current of 2 ampere is passed through it, the resulting magnetic flux linked with each tum of the solenoid is 4 x 10-3 Wb. The self-inductance of the solenoid is
detailed solution
Correct option is A
Total flux ϕ = LI⇒L=ϕI=4 x 10-3 x 5002=1 HTalk to our academic expert!
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A coil is wound as a transformer of rectangular cross-section. If all the linear dimensions of the transformer are increased by a factor 2 and the number of turns per unit length of the coil remain the same, the self inductance increased by a factor of
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