Q.
A long solenoid has 1000 turns. When a current of 4 A flows through it, the magnetic flux linked with each turn of the solenoid is 4×10-3 Wb. The self-inductance of the solenoid is
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a
2H
b
1H
c
4H
d
3H
answer is B.
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Detailed Solution
Here, N=1000,I=4 A,ϕ0=4×10-3 Wb Total flux linked with the solenoid, ϕ=Nϕ0=1000×4×10-3 Wb=4 Wb Since, ϕ=LI∴ Self-inductance of solenoid, L=ϕI=4 Wb4 A=1H
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