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A long solenoid has 1000 turns. When a current of 4 A flows through it, the magnetic flux linked with each turn of the solenoid is . The self-inductance of the solenoid is
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Correct option is B
Here, N=1000,I=4 A,ϕ0=4×10-3 Wb Total flux linked with the solenoid, ϕ=Nϕ0=1000×4×10-3 Wb=4 Wb Since, ϕ=LI∴ Self-inductance of solenoid, L=ϕI=4 Wb4 A=1HSimilar Questions
A solenoid of 1 . 5 metre length and 4 .0 cm diameter possesses 10 turns per cm. A current of 5 ampere is flowing through it. The magnetic field at axis inside the solenoid is (Given: weber/amp metre)
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