Download the app

Questions  

A long solenoid having 200 turns per cm carries a current of 1.5 amp. At the centre of it is placed a coil of 100 turns of cross-sectional area 3.14×104m2 having its axis parallel to the field produced by the solenoid. When the direction of current in the solenoid is reversed within 0.05sec, the induced em.f. in the coil is

a
0.48 V
b
0.048 V
c
0.0048 V
d
48 V

detailed solution

Correct option is B

B=μ0 n i=(4π×10−7)(200×10−2)×1.5 =3.8×10−2Wb/m2ϕ=BA=3.8×10-2×3.14×10-4=1.2×10-5wbMagnetic flux current in the solenoid is reversed, the change in magnetic flux=2×(1.2×10−5)=2.4×10−5weberInduced e.m.f.=Ndodt=100×2.4×10−50.05=0.048V

Talk to our academic expert!

+91

Are you a Sri Chaitanya student?


Similar Questions

A square wire loop, of side a has a long straight wire carrying a constant current i that passes through the centre of the loop and perpendicular to its plane as shown in Fig.

The current induced in the square loop is


phone icon
whats app icon