Questions
A long solenoid of length L, cross-section A having N1 tums has wound about its centre is small coil of N2 turns as shown in fig.(10). Then the mutual inductance of two circuits is
detailed solution
Correct option is B
Magnetic flux at the centre of solenoidB1=μ0N1/Li1Magnetic flux through each turn of the coil of area AΦ1=B1A=μ0N1i1L×AMagnetic flux linked with the coil of turns N2Φ2=Φ1×N2=μ0N1N2i1ALAccording to the definition of mutual inductanceΦ2=Mi1∴Mi1=μ0N1N2i1LA or M=μ0N1N2ALTalk to our academic expert!
Similar Questions
Two circular coils can be arranged in any of the three situations shown in fig.. Their mutual
inductance will be
799 666 8865
support@infinitylearn.com
6th Floor, NCC Building, Durgamma Cheruvu Road, Vittal Rao Nagar, HITEC City, Hyderabad, Telangana 500081.
free study material
JEE Mock Tests
JEE study guide
JEE Revision Notes
JEE Important Questions
JEE Sample Papers
JEE Previous Year's Papers
NEET previous year’s papers
NEET important questions
NEET sample papers
NEET revision notes
NEET study guide
NEET mock tests
