First slide

Work done by Diff type of forces

Question

A long spring is stretched by 2 cm. Its potential energy is U. If the spring is stretched by 10 cm, its
potential energy would be

Easy

A

$\frac{U}{25}$
B

$\frac{U}{5}$
C

U
D

25 U

Solution

Potential energy of the spring, $U = \frac{1}{2} k x^{2} or U \propto x^{2}$
Stretch is increased by 5 times. Therefore, stored potential energy will be increased by 25 times.

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