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Q.

A long spring is stretched by 2 cm. Its potential energy is U. If the spring is stretched by 10 cm, the potential energy stored in it will be

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a

U/25

b

U/5

c

5U

d

25U

answer is D.

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Detailed Solution

We know that, Energy stored=12kx2 U=12k(2)2  and  U1=12k(10)2=2512k(2)2 ∴ U1=25U
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A long spring is stretched by 2 cm. Its potential energy is U. If the spring is stretched by 10 cm, the potential energy stored in it will be