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A long straight current carrying conductor has a radius R. Magnetic field at a distance 2R from the axis of the conductor is 10 μT. Then magnetic field at a distance R/2 from the axis of the conductor is

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Detailed Solution

μ0i2π(2R)=B⇒μ0i=4πRB=4πR x 10=40πR unit∴At a distance R/2 from the axis of the conductor B'=μ02iπR2.R2=14(μ0i).1πR=14 x 40πR x 1πR=10 μT

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