First slide
Magnetic field due to a straight current carrying wire
Question

A long, straight, hollow conductor tube carrying a current has two sections A and C of unequal cross section joined by a conical section B. 1, 2 and 3 are the points on a line parallel to the axis of the conductor. The magnetic fields at 1, 2 and 3 have magnitude B1, B2 and B3 :

Moderate
Solution

Current not depends on area of cross section of wire

 So IA=IB=IC=I and BI

 Hence, B1=B2=B3

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