A long, straight, hollow conductor tube carrying a current has two sections A and C of unequal cross section joined by a conical section B. 1, 2 and 3 are the points on a line parallel to the axis of the conductor. The magnetic fields at 1, 2 and 3 have magnitude B1, B2 and B3 :
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a
B1=B2=B3
b
B1=B2≠B3
c
B1
d
B1>B2>B3
answer is A.
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Detailed Solution
Current not depends on area of cross section of wire So IA=IB=IC=I and B∝I. Hence, B1=B2=B3