Questions
A long straight metal rod has a very long hole of radius drilled parallel to the rod axis as shown in the figure. If the rod carries a current I, find the magnetic field on axis of hole. Given C is the centre of the hole and OC = c.
detailed solution
Correct option is B
In the rod, current densityj=iπb2−a2Actual field at any point in the cylindrical cavity is the vector sum of two current carrying rods, having same current density but in opposite direction. On the hole axis, only the larger rod contributes magnetic field.∮B→. dl→ = μ0ienclosedB2πc= μ0 jπc2B=μ0iπc22πcx b2−a2 = μ0ic2π b2−a2B=μ0ic2π b2−a2Talk to our academic expert!
Similar Questions
Magnetic induction on the surface of a long current carrying wire of radius R is 8 µT. Then magnetic induction at a distance R/4 from the axis of the conductor is
799 666 8865
support@infinitylearn.com
6th Floor, NCC Building, Durgamma Cheruvu Road, Vittal Rao Nagar, HITEC City, Hyderabad, Telangana 500081.
JEE Mock Tests
JEE study guide
JEE Revision Notes
JEE Important Questions
JEE Sample Papers
JEE Previous Year's Papers
NEET previous year’s papers
NEET important questions
NEET sample papers
NEET revision notes
NEET study guide
NEET mock tests