A long straight non-conducting string carries a charge density of 40 μC m-1 . It is pulled along its length at a speed of 300 m/sec, then the magnetic field at a normal distance of 5 mm from the moving string is p×10−7T. Then find the value of p.

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answer is 0004.80.

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Detailed Solution

The moving string behaves like a current, i=qt=qL×Lt=λ×v = (40×10−6C/m)(300 m/sec)=1.2×10−2 AThen B=μ0i2πr=2×10−7×1.2×10−20.005 =4.8×10−7tesla.

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