A long straight non-conducting string carries a charge density of 40 μC m-1 . It is pulled along its length at a speed of 300 m/sec, then the magnetic field at a normal distance of 5 mm from the moving string is p×10−7T. Then find the value of p.
see full answer
High-Paying Jobs That Even AI Can’t Replace — Through JEE/NEET
🎯 Hear from the experts why preparing for JEE/NEET today sets you up for future-proof, high-income careers tomorrow.
An Intiative by Sri Chaitanya
answer is 0004.80.
(Unlock A.I Detailed Solution for FREE)
Best Courses for You
JEE
NEET
Foundation JEE
Foundation NEET
CBSE
Detailed Solution
The moving string behaves like a current, i=qt=qL×Lt=λ×v = (40×10−6C/m)(300 m/sec)=1.2×10−2 AThen B=μ0i2πr=2×10−7×1.2×10−20.005 =4.8×10−7tesla.