A long straight wire along the z-axis carries a current I in the negative z direction. The magnetic vector field B→ at a point having coordinates (x, y) in the z = 0 plane is
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a
μ0I yi^−xj^2πx2 +y2
b
μ0I xi^+yj^2πx2 +y2
c
μ0I xj^+yi^2πx2 +y2
d
μ0I xi^−yj^2πx2 +y2
answer is A.
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Detailed Solution
Magnetic field at Pis B→, perpendicular to OP in the direction shown in figure.So, B→ = B sin θi^ − B cos θ j^Here B= μ02π Irsin θ = yr and cos θ = xr∴ B→=μ02π . Ir2 yi^−xj^ = μ0Iyi^−xj^ 2π x2 + y2 as r2 = x2 + y2
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A long straight wire along the z-axis carries a current I in the negative z direction. The magnetic vector field B→ at a point having coordinates (x, y) in the z = 0 plane is