Q.

A long straight wire carries a certain current and produces a magnetic field2×10-4 Weber m2 at a perpendicular distance of 5 cm from the wire. An electron situated at 5 cm from the wire moves with a velocity 107m/s towards the wire along perpendicular to it. The force experienced by the electron will be (charge on electron 1.6×10-19C)

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a

3.2 N

b

3.2×10-16 N

c

1.6×10-16 N

d

zero

answer is B.

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Detailed Solution

The situation is as shown in the figure. Here, v=107 m/s,B=2×10-4 Wb/m2  The magnitude of the force experienced by the electron is F=evBsinθ  (∴v→ and B are perpendicular to each other) =evBsin90° =1.6×10-19×107×2×10-4×1 =3.2×10-16 N
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