A long straight wire carries a certain current and produces a magnetic field2×10-4 Weber m2 at a perpendicular distance of 5 cm from the wire. An electron situated at 5 cm from the wire moves with a velocity 107m/s towards the wire along perpendicular to it. The force experienced by the electron will be (charge on electron 1.6×10-19C)
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a
3.2 N
b
3.2×10-16 N
c
1.6×10-16 N
d
zero
answer is B.
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Detailed Solution
The situation is as shown in the figure. Here, v=107 m/s,B=2×10-4 Wb/m2 The magnitude of the force experienced by the electron is F=evBsinθ (∴v→ and B are perpendicular to each other) =evBsin90° =1.6×10-19×107×2×10-4×1 =3.2×10-16 N