First slide
Force on a charged particle moving in a magnetic field
Question

A long straight wire carries a certain current and produces a magnetic field2×10-4 Weber m2 at a perpendicular distance of 5 cm from the wire. An electron situated at 5 cm from the wire moves with a velocity 107m/s towards the wire along perpendicular to it. The force experienced by the electron will be (charge on electron 1.6×10-19C)

Moderate
Solution

The situation is as shown in the figure.

 Here, v=107 m/s,B=2×10-4 Wb/m2  The magnitude of the force experienced by the electron is F=evBsinθ  (v and B are perpendicular to each other) =evBsin90° =1.6×10-19×107×2×10-4×1 =3.2×10-16 N

Get Instant Solutions
When in doubt download our app. Now available Google Play Store- Doubts App
Download Now
Doubts App