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Q.

A long straight wire carries a current, I = 2 ampere. A semi-circular conducting rod is placed beside it on two consuding parallel rails of negligible resistance. Both the rails are parallel to the wire. The wire, the rod and the rails lie in the same horizontal plane, as shown in the figure. Two ends of the semi-circular rod are at distances 1 cm and4 cm from the wire. At time t = 0, the rod starts moving on the rails with a speed v = 3.0 m/s (see the figure).A resistor R=1.4Ω and a capacitor C0=5.0μF are connected in series between the rails.At time t = 0, C0 is uncharged. Which of the following statement(s) is(are) correct ?μ0=4π×10−7 SI units. Take ln⁡2=0.7

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a

Maximum current through R is 1.2×10−6 ampere

b

Maximum current through R is 3.8×10−6 ampere

c

Maximum charge on capacitor C0 is 8.4×10−12 coulomb

d

Maximum charge on capacitor C0 is 2.4×10−12 coulomb

answer is A.

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Detailed Solution

→ Here V is instantaneous velocityEmf⁡AB=∫(V¯×B¯)⋅dx =V∫μ0i2πxdxε=μ0iV2πln⁡(4)ε−i1R=qC⇒i1=dqdt ……..(i)ε=μ0i2π(ℓn4)(V) For maximum charge dqdt=i1=0 From (1) ε=qCImax=μ0iV2πln⁡(4)×C0=8.4×10−12CFor maximum current q = 0⇒ i1=εR;μ0iV2πln⁡(4)R=1.2×10−6Amp
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