A long straight wire of resistance R, radius a and length l carries a constant current I. The poynting vector for the wire will be
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a
IR2πal
b
IR2al
c
I2Ral
d
I2R2πal
answer is D.
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Detailed Solution
Electric field, E=Vl=IRl (R = Resistance of wire)Magnetic field at the surface of wire, B=μ0I2πa (a = radius of wire)Hence, poynting vector, directed radially inward is given by S=EBμ0=IRμ0l⋅μ0I2πa=I2R2πal