Questions

A long wire carries a current of 20 A along the axis of solenoid. The field due to the solenoid is 4 mT. The resultant field at a point 3 mm from the solenoid axis is

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1.33mT

4.2mT

5 . 33 mT

2 .87 mT

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detailed solution

Correct option is B

Field due to the wireB is given byBwire =μ04π×2ir=10−7×2×203×10−3T=43×10−3T=43mTField due to solenoid is 4 mT∴ Net magnetic field =BW2+BS2 B=(4/3)2+(4)21/2=4⋅2mT

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