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A long wire carries a current of 20 A along the axis of a solenoid. The field due to the solenoid is 4 mT. The resultant field at a point 3 mm from the solenoid axis is

a
1.33mT
b
4.2 mT
c
2.1mT
d
8.4mT

detailed solution

Correct option is B

The fielddue to wire is given byBwire =μ04π×2ir tesla =10−7×2×203×10−3=1.33×10−3T=4/3mTField due to solenoidBsol = 4mTResultant magnetic field =Bwire 2+Bsol 2=(4/3)2+(4)2mT=4⋅2mT

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