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A long wire carries a steady Current. It is bent into a circle of one turn and the magnetic field at the centre of the coil is B. It is then bent into a circular loop of n turns. The magnetic field at the centre of the coil will be
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a
nB
b
n2 B
c
2 n B
d
2n2B
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Correct option is B
Bcentre =μ0ni2aor B=μ0i2a (∵n=1)When the wire is turned into a circular loop of n turns, then radius o becomes (a / n)∴ Magnetic field, Bn=μ0ni2(a/n)=μ0n2i2a∴ Bn=n2BSimilar Questions
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