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Q.

A long wire carries a steady current. It is bent into a circle of one turn and the magnetic field at the centre of the coil is B. It is then bent into a circular loop of n turns. The magnetic field at the centre of the coil will be

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a

nB

b

n2B

c

2nB

d

2n2B

answer is B.

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Detailed Solution

Magnetic field at the centre of n tum loop Bn= μ04π . 2πir/n × n ⇒  Bn = n2 B
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