First slide

Magnetic field due to a current carrying circular ring

Question

A long wire carries a steady current. It is bent into a circle of one turn and the magnetic field at the centre of the coil is B. It is then bent into a circular loop of n turns. The magnetic field at the centre of the coil will be

Moderate

A

nB
B

n²B
C

2nB
D

2n²B

Solution

Magnetic field at the centre of n tum loop $B_{n} = (\frac{μ_{0}}{4 π} . \frac{2 πi}{r / n}) \times n \Rightarrow B_{n} = n^{2} B$

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