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The longitudinal strain in a metal bar is 0. 6. If the Poisson’s ratio for the metal is 0.20, the lateral strain is

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a
0. 2
b
0.02
c
0.01
d
0.12

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detailed solution

Correct option is D

Δrr=σΔℓℓ =0.20×0.6=0.12


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