The loop ABCDOA is carrying a current i. Radius of arc AB is R, and that of the arc CD is 2R. Then magnetic induction at point O is (O is the common centre of the arcs).
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a
5μ0i16R
b
3μ0i8R
c
3μ0i16R
d
5μ0i8R
answer is C.
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Detailed Solution
the parts AD and BC cannot produce any magnetic induction at point O.∴B0=μ0i2R.π/22π+μ0i2(2R).π/22π= 3μ0 i16