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Loop A of radius r <

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a

R

b

R2

c

R2

d

R1-12

answer is C.

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Detailed Solution

ϕA=μ0iπR22π(R2+x2)3/2πr2⇒EA=-dϕdt=-μ0iπ2R2r2(-3/2)(R2+x2)-5/22xEA is maximum when dEAdx=0⇒ddxx(R2+x2)5/2=0or (R2+x2)5/2-5x2(R2+x2)3/22x=0or, R2+x2-5x2=0or, x=R2

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Loop A of radius r <