A loss free transformer has 500 turns on its primary winding and 2500 in secondary. The meters of the secondary indicate 200 volts at 8 amperes under these conditions. The voltage and current in the primary is
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a
100 V, 16 A
b
40 V, 40 A
c
160 V, 10 A
d
80 V, 20 A
answer is B.
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Detailed Solution
VpVs=NpNs=5002500=15⇒Vp=2005=40 V Also ipVp=isVs⇒ip=isVsVp=8×5=40A