First slide

Electrical machines and devices

Question

A loss free transformer has 500 turns on its primary winding and 2500 in secondary. The meters of the secondary indicate 200 volts at 8 amperes under these conditions. The voltage and current in the primary is

Moderate

A

100 V, 16 A
B

40 V, 40 A
C

160 V, 10 A
D

80 V, 20 A

Solution

$\frac{V_{p}}{V_{s}} = \frac{N_{p}}{N_{s}} = \frac{500}{2500} = \frac{1}{5} \Rightarrow V_{p} = \frac{200}{5} = 40 V$
$Also i_{p} V_{p} = i_{s} V_{s} \Rightarrow i_{p} = i_{s} \frac{V_{s}}{V_{p}} = 8 \times 5 = 40 A$

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