Lower end of a vertical capillary tube is immersed in water and the mass of water that rises in the tube is m. Now the tube is tilted so that it makes an angle of 30o with the horizontal. Then mass of water that rises in the tube is
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a
2m3
b
2m
c
3m
d
23m
answer is B.
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Detailed Solution
If h be the capillary rise in the vertical tube, then m=πr2.h.ρ=πr2.2Tρrg.ρ=2πrTgWhen the tube is tilted, let x be the length and m' be the mass of water column in the tube∴2πrT=m'gsin30o⇒m'=4πrTg=2m