Lower end of a vertical tube with both ends open is submerged in water and the length of air column in it is 32cm. This air column resonates with a tuning fork of frequency 256Hz. The tube is gradually lifted from water so that when the length of air column is increased to 100cm, This air column again resonates with same tuning fork. Then end correction will be

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3 cm

2 cm

2.5 cm

3.2 cm

answer is B.

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Detailed Solution

e+l1=1.v4f ........(1)e+l2=3.v4f ........(2)∴e+l2=3e+l1⇒e=l2-3l12=100-3 x 322cm⇒e=2 cm

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