First slide

Elastic Modulie

Question

A 5 m aluminium wire ( Y= 7 x 10¹⁰N/m²) of diameter 3 mm supports a 40 kg mass. In order to have the same elongation in a copper wire (Y = 12 x 10¹⁰ N/m²) of the same length under the same weight, the diameter should be (in mm):

Easy

A

1.75
B

2.0
C

2.3
D

5.0

Solution

$∆ l = \frac{FL}{AY} \Rightarrow D \infty \frac{1}{\sqrt{Y}}$
$A_{1} Y_{1} = A_{2} Y_{2}$

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