M is a fixed wedge. Masses $$m1$$ and $$m2$$ are connected by a light string. The wedge is smooth and the pulley is smooth and fixed. $$m1$$ $$=$$ $$l0$$ kg and $$m2$$ $$=$$ $$7.5$$ kg. When $$m2$$ is just released, the distance it will travel in $$2$$ seconds is

Question

M is a fixed wedge. Masses $$m1$$ and $$m2$$ are connected by a light string. The wedge is smooth and the pulley is smooth and fixed. $$m1$$ $$=$$ $$l0$$ kg and $$m2$$ $$=$$ $$7.5$$ kg. When $$m2$$ is just released, the distance it will travel in $$2$$ seconds is

Infinity Learn · Accepted Answer

F.B.D of $$m1$$ and $$m2Equation$$ of motionFor  $$m1$$ : T $$-m1g(12)$$ $$=$$ $$m1a-----(i)For$$ $$m2$$ : $$m2g$$ $$-T$$ $$=$$ $$m2a------(ii)From$$ (i) and (ii), a $$=$$ (m2-m12)(m1+m2)g$$  $$=$$ $$107m/s2Hence$$ distance travelled by block $$m2$$ in $$2$$ $$sec$$; usings $$=$$ $$ut+12at2s$$ $$=$$ $$0$$×$$2+12(107)×$$(2)2$$ $$=$$ $$207m$$ $$=$$ $$2.8$$ m

M is a fixed wedge. Masses $m_{1} and m_{2}$ are connected by a light string. The wedge is smooth and the pulley is smooth and fixed. $m_{1} =$ l0 kg and $m_{2} =$ 7.5 kg. When $m_{2}$ is just released, the distance it will travel in 2 seconds is

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M is a fixed wedge. Masses m1 and m2 are connected by a light string. The wedge is smooth and the pulley is smooth and fixed. m1 = l0 kg and m2 = 7.5 kg. When m2 is just released, the distance it will travel in 2 seconds is

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Ready to Test Your Skills?

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M is a fixed wedge. Masses $m_{1} and m_{2}$ are connected by a light string. The wedge is smooth and the pulley is smooth and fixed. $m_{1} =$ l0 kg and $m_{2} =$ 7.5 kg. When $m_{2}$ is just released, the distance it will travel in 2 seconds is