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Force on a current carrying wire placed in a magnetic field

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Question

A 0.1 m long conductor carrying a current of 50A is perpendicular to a magnetic field of 1.25mT. The mechanical power to move the conductor with a speed of 1 m/s in a direction perpendicular to its length and perpendicular to its length and perpendicular to the magnetic field is,

Moderate
Solution

Magnetic force FB=ilB=50×0.1×1.25×103N=6.25×103N

PowerFB×v=6.25×103×1J=6.25mW


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