A 0.1 m long conductor carrying a current of 50 A is perpendicular to a magnetic field of 1.21 mT. The mechanical power to move the conductor with a speed of 1 m s-1 is
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a
0.25 mW
b
6.25 mW
c
0.625 W
d
1 W
answer is B.
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Detailed Solution
Power = ( Bil ) . v = 1.21×10-3×50×0.1×1=6.25×10-3T
A 0.1 m long conductor carrying a current of 50 A is perpendicular to a magnetic field of 1.21 mT. The mechanical power to move the conductor with a speed of 1 m s-1 is