Banner 0
Banner 1
Banner 2
Banner 3
Banner 4
Banner 5
Banner 6
Banner 7
Banner 8
Banner 9

Q.

A 0.1 m long conductor carrying a current of 50 A is perpendicular to a magnetic field of 1.21 mT. The mecha­nical power to move the conductor with a speed of 1 m s-1 is

see full answer

Your Exam Success, Personally Taken Care Of

1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya

a

0.25 mW

b

6.25 mW

c

0.625 W

d

1 W

answer is B.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

JEE

NEET

NEET

Foundation JEE

Foundation JEE

Foundation NEET

Foundation NEET

CBSE

CBSE

Detailed Solution

Power = ( Bil ) . v = 1.21×10-3×50×0.1×1=6.25×10-3T
Watch 3-min video & get full concept clarity
score_test_img

courses

No courses found

Get Expert Academic Guidance – Connect with a Counselor Today!

best study material, now at your finger tips!

  • promsvg

    live classes

  • promsvg

    progress tracking

  • promsvg

    24x7 mentored guidance

  • promsvg

    study plan analysis

download the app

gplay
mentor

Download the App

gplay
whats app icon
personalised 1:1 online tutoring
A 0.1 m long conductor carrying a current of 50 A is perpendicular to a magnetic field of 1.21 mT. The mecha­nical power to move the conductor with a speed of 1 m s-1 is