Questions
A 0.1 m long conductor carrying a current of 50 A is perpendicular to a magnetic field of 1.21 mT. The mechanical power to move the conductor with a speed of 1 m is
detailed solution
Correct option is B
Power = ( Bil ) . v = 1.21×10-3×50×0.1×1=6.25×10-3TTalk to our academic expert!
Similar Questions
A copper rod AB of length 2m is moving in a uniform magnetic field of 1.5 T with a velocity of 3 m/s. The induced potential difference between ends A and B is
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