First slide
Motional EMF
Question

A 0.1 m long conductor carrying a current of 50 A is perpendicular to a magnetic field of 1.21 mT. The mecha­nical power to move the conductor with a speed of 1 m s-1 is 

Easy
Solution

Power = ( Bil ) . v = 1.21×10-3×50×0.1×1=6.25×10-3T

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