A 2 m long rod of radius I cm which is fixed from one end is given a twist of 0.8 radians. The shear strain developed will be
0.002
0.004
0.008
0.016
rθ = Lϕ ⇒ 10-2×0.8 = 2×ϕ ⇒ ϕ = 0.004