A 200 m long train starts from rest at t = 0 with constant acceleration 4 cm s-2. The head light of its engine is switched on at t = 60 s and its tail light is switched on at t = 120 s. Find the distance (in meter) between these two events for an observer standing on the platform.

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answer is 16.

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Detailed Solution

The distance travelled by the head light of engine in 60 s iss1=ut+12at2=0×60+12×0.04×(60)2=72mThe distance travelled by tail light of the train in 120 s iss2=ut+12at2=0×120+12×0.04×(120)2=288mThus, the distance between these two events={288-(200+72)}m=16m

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