First slide

Specific heat

Question

0.1 m³ of water at 80°C is mixed with 0.3 m³ of water at 60°C. The final temperature of the mixture is:

Easy

A

65°C
B

70°C
C

60°C
D

75°C

Solution

Heat lost = Heat gained
$\Rightarrow (0.1) ρ \times s \times (80 - θ) = (0.3) ρ \times s \times (θ - 60) \Rightarrow θ = 65^{o} C$

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Recieve an sms with download link

Doubts App

OR

SCAN ME

Doubts App

Doubts App