First slide

Third law

Question

A machine gun fires a bullet of mass 40 g with a velocity 1200 m/s. The man holding it can exert a maximum force of 144 N on the gun. How many bullets can he fire per second at the most?

Moderate

A

one
B

four
C

two
D

three

Solution

Let n bullets be fired per second. We know that rate of change of momentum is equal to force. Hence
$\frac{40}{1000} \times 1200 \times n = 144$
$∴ 48 n = 144 or n = 3$ .

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