A machine gun fires a bullet of mass 40 g with a velocity 1200 m/s. The man holding it can exert a maximum force of 144 N on the gun. How many bullets can he fire per second at the most?
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a
one
b
four
c
two
d
three
answer is D.
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Detailed Solution
Let n bullets be fired per second. We know that rate of change of momentum is equal to force. Hence401000×1200×n=144∴48n=144 or n=3.