First slide

Third law

Question

A machine gun fires a bullet of mass 40 g with a velocity 1200 $m s^{- 1}$ .The man holding it can exert a maximum force of 144 N on the gun. How many bullets can be fired per second at the most?

Moderate

A

Only one
B

Three
C

Can fire any number of bullets
D

144 x 48

Solution

Given, $m_{b} = 40 g, v_{b} = 1200 {ms}^{- 1}$
F = 144 N
$∴ F = n m a = \frac{m_{b} ν_{b}}{t} \times n$
$\Rightarrow 144 = \frac{40 \times 1200}{1000} \times n \Rightarrow n = 3$

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