Q.

A machine gun fires a bullet of mass 40 g with a velocity  1200  ms−1.The man holding it can exert a maximum force of 144 N on the gun. How many bullets can he fire per second at the most

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a

One

b

Four

c

Two

d

Three

answer is D.

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Detailed Solution

u = velocity of bulletdmdt=Mass fired per second by the gundmdt=Mass of bullet (mB) × Bullets fired per sec (N)Maximum force that man can exert F=u dmdt∴F=u×mB×N⇒N=FmB×u=14440×10−3×1200=3
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A machine gun fires a bullet of mass 40 g with a velocity  1200  ms−1.The man holding it can exert a maximum force of 144 N on the gun. How many bullets can he fire per second at the most