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A machine gun fires a bullet of mass 40 g with a velocity 1200 ms-1. The man holding it can exert a maximum force of 144 N on the gun. How many bullets can he fire per
second at the most? 

a
One
b
Four
c
Two
d
Three

detailed solution

Correct option is D

u = Velocity of bulletdmdt=Mass fired per second by the gun Mass of bullet mB× Bullets fired per sec⁡(N)Maximum force that man can exert, F=udmdt∴     F=u×mB×N⇒     N=FmB×u=14440×10−3×1200=3

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