Questions
A machine gun fires a bullet of mass 40 gm with a speed 1200 m/s. The man holding it can exert a maximum force of 144 N on the gun. How many bullets can he fire per second at the most?
detailed solution
Correct option is D
F=ΔpΔt=mnv1⇒n=Fmv=14440×10−3(1200)=3Talk to our academic expert!
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