First slide

Second law

Question

A machine gun fires a bullet of mass 40 gm with a speed 1200 m/s. The man holding it can exert a maximum force of 144 N on the gun. How many bullets can he fire per second at the most?

Easy

A

One
B

Four
C

Two
D

Three

Solution

$F = \frac{Δp}{Δt} = \frac{mnv}{1} \Rightarrow n = \frac{F}{mv} = \frac{144}{(40 \times 10^{- 3}) (1200)} = 3$

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