A magnet is $$10$$ cm long and its pole strength is $$120$$ CGS $$units(1$$ CGS unit of pole $$strength=0.1$$ $$Am)$$. Find the magnitude of magnetic field ‘B’ at a point on its axis at a distance $$20$$ cm from it.

Question

Infinity Learn · Accepted Answer

The pole strength is $$m=120$$ CGS $$units=$$ $$12$$ AmMagnetic length (distance$$ between $$poles) is $$2l=10$$ cm or  $$l=0.05$$ mDistance from the center of magnet is $$d=20$$ $$cm=0.2$$ m.The field B at a point on axial position is $$B=$$μ$$04$$π$$.2Mdd2$$−$$l22$$ ⇒$$B=$$μ$$04$$π$$.4mldd2$$−$$l22$$ ⇒$$B=10$$−$$7.4$$×$$12$$×$$0.05$$×$$0.2(0.2)2$$−$$(0.05)22B=3.4$$×$$10$$−$$5$$ T .

A magnet is 10 cm long and its pole strength is 120 CGS units(1 CGS unit of pole strength=0.1 Am). Find the magnitude of magnetic field ‘B’ at a point on its axis at a distance 20 cm from it.

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