The magnet field at a point x on the axis of a small bar magnet is equal to the field at a point y on the equator of the same magnet. The ratio of the distances of x and y from the centre of the magnet is

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2-3

2-1/3

21/3

answer is D.

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Detailed Solution

Ba=μ04π2Mx3 and Be=μ04πMy3 As Ba=BeHence, 2Mx3=My3 or x3y3=2 or xy=21/3

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