A magnet of length L and Moment M is cut into two halves perpendicular to its axis. One piece A is bent into a semicircle of radius R and is joined to the other piece at the poles as shown. The moment of the resulting magnet is,
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a
M2π
b
Mπ
c
M(2+π)2π
d
Mπ2+π
answer is C.
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Detailed Solution
Magnetic Moment is proportional to Magnetic Length∴MB =M/2 For A, Magnetic length =2R where πR=L2⇒R= L2π ⇒Magnetic length =2R = L/π ∵ Magnetic Moment is proportional to Magnetic Length ∴MA = LπL ×M = MπHence, M1 = MA + MB = Mπ + M2 = M(2+π)2π