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Q.

A magnet of length L and Moment M is cut into two halves perpendicular to its axis. One piece A is bent into a semicircle of radius R and is joined to the other piece at the poles as shown. The moment of the resulting magnet is,

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a

M2π

b

c

M(2+π)2π

d

Mπ2+π

answer is C.

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Detailed Solution

Magnetic  Moment  is  proportional  to  Magnetic  Length∴MB ​=M/2 ​For A,  ​Magnetic  length =2R ​where πR=L2​⇒R=  L2π  ​   ​⇒Magnetic  length =2R =  L/π  ​∵  Magnetic  Moment  is  proportional  to  Magnetic  Length ​∴MA ​  =  LπL ×M ​  = MπHence, M1 = MA + MB = Mπ + M2 = M(2+π)2π
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