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A magnet of length 0. 1 m and pole strength $10^{- 4} Am$ is kept in a magnetic field of $30 Wb / m^{2}$ at an angle $30^{o}$ . The couple acting on it is . $. . x l 0^{- 4} N m$ .

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detailed solution

Correct option is C

τ=MBsinθ=m x (2l) x B sinθ=10-4 x 0.1 x 30 sin30o =1.5 x 10-4 Nm

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A magnet of length 0. 1 m and pole strength 10-4 Am is kept in a magnetic field of 30 Wb/m2 at an angle 30o. The couple acting on it is ... x l0-4N m.

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A magnet of length 0. 1 m and pole strength $10^{- 4} Am$ is kept in a magnetic field of $30 Wb / m^{2}$ at an angle $30^{o}$ . The couple acting on it is . $. . x l 0^{- 4} N m$ .