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A magnet of length 0.1 m and pole strength 50 Am is kept in a magnetic field 4 ×10-5  T at an angle 300 to it. The couple acting on it is

a
10-4 Nm
b
10-1 Nm
c
10-2 Nm
d
10-3 Nm

detailed solution

Correct option is A

M=50×0.1 = 5B = 4×10−5Tτ = MBSinθ = 4×10−5×5×12=10×10−5 = 10−4N−m

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