First slide

Magnetic dipole in a uniform magnetic field

Question

A magnet of length 0.1 m and pole strength 50 Am is kept in a magnetic field $4 \times 10^{- 5}$ T at an angle $30^{0}$ to it. The couple acting on it is

Easy

A

$10^{- 4} N m$
B

$10^{- 1} N m$
C

$10^{- 2} N m$
D

$10^{- 3} N m$

Solution

$M = 50 \times 0.1 = 5$
$B = 4 \times 10^{- 5} T$
$τ = M B Sin θ = 4 \times 10^{- 5} \times 5 \times \frac{1}{2}$
$= 10 \times 10^{- 5} = 10^{- 4} N - m$

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