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Questions  

A magnet of magnetic moment M is freely suspended in a constant uniform magnetic field of intensity H. magnet is deflected by an angle θ  from direction of H. the work done is

a
MH  cos  θ
b
MH  (1−cos  θ)
c
MH  sin  θ
d
MH  (1−sin  θ)

detailed solution

Correct option is B

θ1=0∘, θ2=θ W=−MH (cos  θ2−cos  θ1)      =−MH (cos θ−cos 0)=MH (1−cos θ)

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