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A magnet of magnetic moment M oscillating freely in earth's horizontal magnetic field makes n oscillations per minute. If the magnetic moment is quadrupled and the earth's field is doubled, the number of oscillations made per minute would be

a
n22
b
n2
c
22n
d
2n

detailed solution

Correct option is C

No. of oscillations per minute = 12πMBHI⇒n∝MBH; M→4 times                          BH →2 timesso v→8 times i.e., v'=8v=22n

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