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Q.

A magnet of magnetic moment M is rotated through 360° in a magnetic field H, the work done will be

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a

MH

b

2MH

c

2πMH

d

Zero

answer is D.

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Detailed Solution

W=MBcosθ1−cosθ2;  θ1=0oand θ2=360o⇒W=0
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