First slide

Magnetic dipole in a uniform magnetic field

Question

A magnet of magnetic moment M is rotated through 360^o in a magnetic field H, the work done will be

Easy

A

MH
B

2MH
C

2 $π$ MH
D

zero

Solution

$W = \int_{0}^{2 π} τdθ = \int_{0}^{2 π} p_{e} E \sin θ dθ = 0$
W = M B ( 1 - C0S $θ$ )=MB(1- 1) COS 360⁰=1

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