A magnet of magnetic moment M is situated with its axis along the direction of a magnetic field of strength B. The work done in rotating it by an angle of 180o will be

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-MB

+MB

+2MB

answer is D.

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Detailed Solution

Work done = MB(cos θ1 - cosθ2)θ1=0o and θ2=180o⇒W=MB(cos0o-cos180o)=2MB

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