A magnet of magnetic moment M is situated with its axis along the direction of a magnetic field of strength B. The work done in rotating it by an angle of 180o will be
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a
-MB
b
+MB
c
0
d
+2MB
answer is D.
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Detailed Solution
Work done = MB(cos θ1 - cosθ2)θ1=0o and θ2=180o⇒W=MB(cos0o-cos180o)=2MB