First slide

Magnetic dipole in a uniform magnetic field

Question

A magnet is suspended horizontally in the earth's magnetic field. When it is displaced and then released, it oscillates in the horizontal plane with a period T If a piece of wood of the same moment of inertia (about the axis of rotation) as the magnet is attached to magnet, what would be the new period of oscillation of the system become ?

Moderate

A

T/3
B

T/2
C

$\frac{T}{\sqrt{2}}$
D

$T \sqrt{2}$

Solution

$\begin{array}{l} T = 2 π \sqrt{(\frac{I}{{MB}_{H}})} and T^{'} = 2 π \sqrt{\frac{2 I}{{MB}_{H}}} \\ ∴ T^{'} = \sqrt{2} \times T \end{array}$

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