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Q.

A magnet is suspended in the magnetic meridian with un twisted wire. The upper end of the wire is rotated through 1800 to deflect the magnet by 300 from magnetic meridian. Now this magnet is replaced by another magnet. Now the upper end of the wire is rotated through 2700 to deflect the magnet 300 from the magnetic meridian. The ratio of the magnetic moments of the two magnets is

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a

3:4

b

1:2

c

4:7

d

5:8

answer is D.

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Detailed Solution

During equilibrium, Torsional torque should be balanced by magnetic torque. C(α-θ)=MBsinθWhere C is the couple per unit deflection & α is the twisted angle, θ is the deflection angleGiven : α1=180°,θ=30°, α2=270° for first magnet C(180-30)=M1Bsin30° for second magnet C(270-30)=M2Bsin30 Dividing, 150240=M1M2=58

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