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Q.

A magnet when placed perpendicular to a uniform field of strength 10-4 Wb/m2 experiences a maximum couple of moment 4 x 10-5 N/m. What is its magnetic moment?

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a

0.4 A m2

b

0.2 A m2

c

0.16 A m2

d

0.04 A m2

answer is A.

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Detailed Solution

τmaximum= MB⇒4 x10-5 =M x 10-4 ⇒M=0.4 Am2
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