Q.
A magnet when placed perpendicular to a uniform field of strength 10-4 Wb/m2 experiences a maximum couple of moment 4 x 10-5 N/m. What is its magnetic moment?
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a
0.4 A m2
b
0.2 A m2
c
0.16 A m2
d
0.04 A m2
answer is A.
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Detailed Solution
τmaximum= MB⇒4 x10-5 =M x 10-4 ⇒M=0.4 Am2
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