First slide

Magnetic dipole in a uniform magnetic field

Question

A magnet when placed perpendicular to a uniform field of strength 10^-4 W/m² experiences a couple of moment 4 x 10^-5 N/m. The magnetic moment is

Easy

A

0.4 amp x m²
B

0.2 amp x m²
C

0.16 amp x m²
D

0.06 amp x m²

Solution

$\begin{array}{l} τ = MBsin θ \\ 4 \times 10^{- 5} = M (10^{- 4}) \sin 90^{\circ} \\ M = 0 \cdot 4 amp \times m^{2} \end{array}$

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